Veiw Answer
**Answer:** 273

**Explanation:**

Let AB be the lighthouse and C and D be the positions of the ships. Then, AB = 100 m, ACB = 30° and ADB = 45°. AB = tan 30° = 1 AC = AB x 3 = 1003 m. AC 3 AB = tan 45° = 1 AD = AB = 100 m. AD CD = (AC + AD) = (1003 + 100) m = 100(3 + 1) = (100 x 2.73) m = 273 m.

Veiw Answer
**Answer: **Data inadequate

**Explanation:**

One of AB, AD and CD must have given. So, the data is inadequate.

Veiw Answer
**Answer:** 9.2 m

**Explanation:**
Let AB be the wall and BC be the ladder.

Then, ACB = 60° and AC = 4.6 m. AC = cos 60° = 1 BC 2 BC = 2 x AC = (2 x 4.6) m = 9.2 m.

Veiw Answer
**Answer:** 21.6 m

**Explanation:**
Let AB be the observer and CD be the tower.

Draw BE CD. Then, CE = AB = 1.6 m, BE = AC = 203 m. DE = tan 30° = 1 BE 3 DE = 203 m = 20 m. 3 CD = CE + DE = (1.6 + 20) m = 21.6 m.

Veiw Answer
**Answer:** 156 m

**Explanation:**

Let AB be the tower. Then, APB = 30° and AB = 100 m. AB = tan 30° = 1 AP 3 AP = (AB x 3) m = 1003 m = (100 x 1.73) m = 173 m.

Veiw Answer
**ANSWER:** 50(root3 - 1)/ root3 m
**Explanation: **

Veiw Answer
** ANSWER: **103 m

**Explanation:**

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